arXiv:0805.4442v1 [math.CO] 28 May 2008
Intersections of Apartments
Peter Abramenko
Hendrik Van Maldeghem∗
Abstract
We show that, if a building is endowed with its complete system of apartments,
and if each panel is contained in at least four chambers, then the intersection of two
apartments can be any convex subcomplex contained in an apartment. This combinatorial result is particularly interesting for lower dimensional convex subcomplexes
of apartments, where we definitely need the assumption on the four chambers per
panel in the building. The corresponding statement is not true anymore for arbitrary systems of apartments, and counter-examples for infinite convex subcomplexes
exist for any type of buildings. However, when we restrict to finite convex subcomplexes, the above remains true for arbitrary systems of apartments if and only if
every finite subset of chambers of the standard Coxeter complex is contained in the
convex hull of two chambers.
1
Introduction
Buildings were defined by Jacques Tits in the sixties as the natural geometric structures
related to groups of Lie type – providing natural permutation modules for these groups.
In this setting, only the spherical buildings are important, and a full classification for
irreducible rank at least three exists, see the seminal monograph [6]. However, it became
clear later that also non-spherical buildings (e.g. affine buildings) play a very important
role in group theory, and we will not make any restrictions concerning the type of the
building in this paper. In the original definition of buildings apartments play a crucial
role. In fact, the two main axioms of buildings in [6] are about apartments. One axiom
states that every pair of chambers is contained in an apartment, and the other that
The second author is partly supported by a Research Grant of the Fund for Scientific Research Flanders (FWO - Vlaanderen)
∗
1
two apartments can be isomorphically mapped onto each other by an isomorphism fixing
two chosen simplices in the intersection and all their faces. Naturally, one can ask which
convex subcomplexes of apartments can be realized as intersections of two apartments. We
provide a complete answer to this question for thick buildings in the present paper. Note
that this result goes a little bit in the opposite direction of the main use of apartments.
Indeed, usually one reduces a problem concerning buildings to a problem in an apartment
— a Coxeter complex. Here, we reduce potential problems involving the intersection of
roots in an apartment (which is by definition a convex subcomplex of that apartment) to
the intersection of just two apartments, but in the whole building.
In the eighties, a local approach to buildings [7], again initiated by Jacques Tits, led the
latter to introduce buildings without mentioning apartments, but using chamber systems.
But around the same time, or even a little bit later, Jacques Tits completed the classification of affine buildings of irreducible rank at least four, and there the apartments play
a prominent role [8]. In fact, they were so important that the class of objects to which
the classification could be applied (this class is slightly larger than that of the affine
buildings) was called systems of apartments by Tits. Later, in the nineties, yet another
definition of buildings was introduced, again by Jacques Tits, this time for the benefit of
twin buildings, which are natural generalizations of spherical buildings, and which are the
natural geometric structures for Kac-Moody groups [9] over fields. That new definition
interprets buildings as W -metric spaces, a point of view which will also be important in
parts of the present paper (see e.g. Lemma 3.7). It again does not explicitly mention
apartments which, however, remain to be an important notion also in this approach .
For instance, together with twin buildings, the notion of a generalized Moufang building
became important. This notion, which was first introduced for spherical buildings in the
appendix of [6], uses in a crucial way so-called roots in a building, which are nothing other
than . . . half-apartments.
So it is clear that the apartments of a building are of vital importance in the whole
theory. Although one sometimes removes them from the definition, in order to make things
simpler, they have remained crucial in the results and the theory. Therefore, the question
of what the intersection of two apartments can be is a fundamental one for all types of
buildings. We answer this question in the present paper. The result is neither surprising
nor difficult to prove if this intersection contains chambers. However, the problem becomes
much more difficult in the case of lower dimensional convex subcomplexes of apartments.
First of all, it is clear that then not every convex subcomplex is an intersection of two
apartments if the building has only three chambers per panel. It is quite surprising that
this is in fact the only obstacle, i.e., in a building with at least four chambers per panel,
any convex subcomplex of an apartment is an intersection of two apartments. In this
2
context ‘apartment’ means ‘member of the complete system of apartments’. If one also
considers arbitrary apartment systems, then the answer becomes more involved, and we
have also dealt with that situation. The simple case of two adjacent chambers — which
is for every building and every apartment system a convex set contained in an apartment
— already has a nice application, as we will show.
The paper is organized as follows. In Section 2 we introduce some basic notions and fix
some notation. We also state our main results and an application. In the rest of the
paper, we then proceed to prove these results. Along the way, we have phrased some
lemmas and propositions slightly more generally then necessary for our purposes, because
we think that these results can be of independent use. For instance, Section 3 deals with
constructing apartments under various conditions — obviously important in this paper,
but potentially also useful in many other situations. In Section 4, we consider the case of
a complete system of apartments, while Section 5 looks at the other situations.
2
Preliminaries and Main Results
We assume that the reader is familiar with basic concepts from building theory, as presented in [2], [5] and [6]. In order to fix some notation and avoid confusion, we will repeat
some of these concepts here. We mainly take the simplicial point of view. So a building
∆ will be a chamber complex which admits a system of apartments satisfying the usual
axioms (see e.g. [6], Chapter 3, or [2], Section 4.1). However, on the one hand, we shall not
always assume that ∆ is thick, but state this condition explicitly whenever needed. On
the other hand, we do assume that ∆ is finite-dimensional. As usual, the top-dimensional
simplices of ∆ are called chambers, the simplices of codimension 1 are called panels, and
∆ is called thick if each panel is contained in at least three chambers. We denote by
C = Ch(∆) the set of chambers of ∆, and, for any chamber subcomplex κ of ∆, by Ch(κ)
the set of chambers of κ. Two chambers are called adjacent if they are different (note
that some authors do not require this) and share a common panel. A gallery (of length
n) is a sequence (C0 , C1 , . . . , Cn ) of n + 1 chambers in which Ci−1 and Ci are adjacent,
for all 1 ≤ i ≤ n. Such a gallery is called minimal if there is no gallery of length < n
starting in C0 and ending in Cn . In this case we also say that n is the (gallery) distance
between C0 and Cn . If two chambers C, D ∈ C are at distance n, we write d(C, D) = n.
A chamber subcomplex κ of ∆ is called convex if for any two chambers C, D of κ, every
gallery (C0 , C1 , . . . , Cn ) in ∆ with C0 = C, Cn = D and n = d(C, D) is contained in κ.
An arbitrary subcomplex κ of ∆ is called convex if it is the intersection of convex chamber
subcomplexes of ∆. This is the definition of convexity given by Tits in [6], Section 1.5,
3
but differs from the one given in [2], Section 4.11. However, if κ contains a chamber or is
contained in an apartment of ∆, these two definitions agree, and in this paper we will only
consider subcomplexes of apartments. For any set S of simplices of ∆, the convex closure
or convex hull of S is defined as the intersection of all convex subcomplexes containing S.
Recall that all apartments of ∆ are Coxeter complexes which are isomorphic to each
other. If they are isomorphic to the standard Coxeter complex Σ(W, S) (as defined in
[2], Section 3.1), where (W, S) is a Coxeter system, we say that ∆ is of type (W, S).
Each building admits a maximal apartment system Ae (see for instance [2], Section 4.5),
which is called the complete system of apartments of ∆. A subset A of Ae is a system of
apartments of ∆ if and only if any two chambers of ∆ are contained in some element of
A. If ∆ is of type (W, S), the elements of Ae are precisely the simplicial subcomplexes of
∆ which are isomorphic to Σ(W, S) (see [2], Proposition 4.59). Whenever we talk about
apartments of ∆ without further specification, we mean elements of the complete system
Ae of apartments of ∆.
We fix an apartment Σ of a building ∆. As a preparation towards our First Main Result,
we shall prove in Section 4:
Proposition 2.1 If ∆ is thick and κ is a convex chamber subcomplex of Σ, then there
exists an apartment Σ′ of ∆ such that κ = Σ ∩ Σ′ .
Remark 2.2 Assume there exists a panel P in Σ which is contained in exactly 3 chambers
of ∆. Then it is obvious that the wall M of Σ containing P cannot be written as M = Σ∩Σ′
for some apartment Σ′ since Σ ∩ Σ′ has to contain at least one of the three chambers
containing P .
So it is clear that Proposition 2.1 cannot be true in general for (lower dimensional) convex
subcomplexes of Σ. Amazingly enough, it turns out to be true if we only add the (obviously
necessary) condition that each panel is contained in at least 4 chambers of ∆.
Theorem 2.3 (First Main Result) Suppose every panel of the building ∆ is contained
in at least 4 chambers. Then for every convex subcomplex κ of Σ, there exists an apartment
Σ′ of ∆ such that κ = Σ ∩ Σ′ .
Now a natural question arises: What can we say if the building ∆ is not endowed with
its complete set of apartments? We will prove that, whenever a convex subcomplex of
an apartment has infinitely many vertices, then Theorem 2.3 does not hold in general
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(when the system of apartments is not complete). In fact, in this case, such a convex
subcomplex might not even be the intersection of all apartments in which it is contained.
Hence we are lead to consider only the case where our convex subcomplex has a finite
number of simplices. Then we will show that every such convex subcomplex (contained
in an apartment of an arbitrarily given apartment system A of ∆) is the intersection of
two apartments of A if and only if the building is a direct product of spherical and affine
buildings. Here is the precise result:
Theorem 2.4 (Second Main Result) Let ∆ be a thick building of type (W, S). Then
the following are equivalent.
(I) For any apartment system A of ∆, the convex closure of two given chambers C and
D is the intersection of two apartments in A.
(II) For any apartment system A of ∆, every convex finite set κ of chambers contained
in some member of A is the intersection of two apartments in A.
(III) For every finite subset F of chambers of the Coxeter complex Σ(W, S), there exist
two chambers C, D ∈ Σ(W, S) such that F is contained in the convex closure of C
and D.
If every panel of ∆ is contained in at least four chambers, and Condition (III) is satisfied,
then every finite convex subcomplex contained in an apartment is the intersection of two
apartments (with respect to any apartment system A).
Now it is proved by Caprace in [4] that Assertion (III) is equivalent to Σ(W, S) having
only spherical and affine components.
We shall also prove the following related result for pairs of adjacent chambers.
Proposition 2.5 Let ∆ be a thick building endowed with an arbitrary system A of apartments. Then the set of two adjacent chambers and all their faces is always the intersection
of all apartments in A in which they are both contained.
As an application of this proposition we shall prove in Section 5:
Proposition 2.6 Every map between the chamber sets of a thick building ∆ and an arbitrary building ∆′ (endowed with arbitrary systems of apartments A and A′ , respectively)
which bijectively maps the set of chambers of any apartment Σ ∈ A to the set of chambers of some apartment Σ′ ∈ A′ is injective and preserves adjacency of chambers. Hence
it induces a simplicial isomorphism of ∆ onto a thick subbuilding of ∆′ in case ∆ is
2-spherical.
5
3
Constructing apartments
In the course of the proof of our main results, we shall make use of some well-known facts,
and some lemmas that might be of independent interest. We collect these assertions in
this section. Most of them are concerned with the construction of apartments containing
certain sets of simplices and satisfying certain conditions.
We start by repeating some more notions from the simplicial theory of buildings. If Σ
is a Coxeter complex, a root of Σ is the image of a folding of Σ (see [6], Chapter 2, or
[2], Section 3.4). It is well known that a subcomplex κ of Σ is convex if and only if it is
an intersection of roots of Σ. If α is a root of Σ, the subcomplex of Σ generated by all
chambers of Σ which are not in α is again a root of Σ, denoted by −α (if Σ is understood)
and called the root opposite α in Σ. The subcomplex α ∩ (−α) is called the boundary or
wall of α (or of −α); it is the subcomplex of Σ generated by all panels in Σ which are
contained in precisely one chamber of α. If ∆ is a building, a root or wall in ∆ is a root
or wall in one of its apartments.
In a Coxeter complex Σ, the support suppA of a simplex A is the intersection of all walls
of Σ containing A. We repeat the following result from [1]:
Proposition 3.1 If κ is a convex subcomplex of a Coxeter complex Σ, A is a maximal
simplex of κ, and M is a wall in Σ containing A, then κ ⊆ M. Hence, κ ⊆ suppA.
Proof. See Proposition 1 (ii) of [1].
In the following, ∆ denotes a building of type (W, S), and C is the set of chambers of ∆.
The following property of apartments is well known if Σ ∩ Σ′ contains chambers, and is
proved in general in [2]:
Proposition 3.2 Let Σ, Σ′ be two apartments of ∆. Then there exists an isomorphism
ϕ : Σ → Σ′ such that ϕ fixes each simplex in Σ ∩ Σ′ .
Proof. See Proposition 4.101 of [2]
Before we continue, we remind the reader that ∆ comes equipped with a Weyl distance
function δ : C × C → W (see [2], Section 4.8). This function δ is an important tool in the
theory of buildings. The latter can, in fact, be based completely on the properties of the
Weyl distance function (see [2], Chapter 5). If ∆ and ∆′ are two buildings of type (W, S)
with chamber sets C and C ′ , and with Weyl distance functions δ and δ ′ , respectively, then
6
two subsets M ⊆ C and M′ ⊆ C ′ are called W -isometric (or just isometric) if there exists
a bijective map f : M → M′ such that δ ′ (f (C), f (D)) = δ(C, D), for all C, D ∈ M. One
of the fundamental facts in this context is that a subset M ⊆ C is contained in Ch(Σ), for
some apartment Σ of ∆, if and only if M is isometric to a subset of W = Ch(Σ(W, S)),
see [5], Theorem 3.6, or [2], Theorem 5.73.
This will be used in the next two propositions.
Proposition 3.3 Given a root α of ∆ with boundary wall M, a panel P ∈ M and a
chamber C containing P but not contained in α, there exists an apartment Σ containing
α ∪ {C}.
Proof. Consider any apartment Σ′ containing α and let D be the chamber in Σ′ containing
P and not contained in α. Then it is clear that Ch(α)∪{C} is W -isometric to Ch(α)∪{D}.
The assertion now follows from Theorem 3.6 in [5].
Proposition 3.4 A subset M of C = Ch(∆) is contained in the set of chambers of some
apartment of ∆ if and only if
(⋆) δ(C, E) = δ(C, D)δ(D, E), for all C, D, E ∈ M.
Proof. This is contained in [2], see Exercise 5.77. We provide a proof for completeness’
sake.
The necessity of Condition (⋆) is clear by standard properties of apartments. To verify
sufficiency, first fix a chamber C0 ∈ M and define a map f : M → W by f (C) = δ(C0 , C)
for all C ∈ M. Due to the Condition (⋆), this is an isometry. Indeed, denoting the
natural Weyl distance on W by δW , we have
δW (f (C), f (D)) = f (C)−1 f (D) = δ(C0 , C)−1 δ(C0 , D)
= δ(C, C0)δ(C0 , D) = δ(C, D).
Slightly abusing notation, we also denote the induced map M → f (M) by f . Then f is
a bijective isometry, so that f −1 : f (M) → M is an isometry. Now, by Theorem 3.6 of
[5], f −1 can be extended to an isometry g : W → C, and hence M is contained in g(W ),
which is the set of chambers of an apartment of ∆.
We now prove some lemmas. Their proofs use projections, a concept which we briefly
recall now (for details, we refer to [6], Chapter 3, or [2], Sections 4.9 and 5.3). Let A, B be
7
simplices of the building ∆. If A and B are chambers, we denote by d(A, B) the gallery
distance between A and B. In general, we define d(A, B) = min{d(C, D) | C, D ∈ C, A ⊆
C and B ⊆ D}. Then there is a unique simplex P containing A with the property that,
for any chamber C containing A, one has d(C, B) = d(A, B) if and only if P ⊆ C. This
simplex P is called the projection of B onto A and denoted by P = projA B. If B is
a chamber, then also projA B is a chamber, and it has the “gate property” d(C, B) =
d(C, projA B) + d(projA B, B), for all chambers C containing A. Moreover, δ(C, B) =
δ(C, projA B)δ(projA B, B) in this case (see [2], Proposition 5.34).
Lemma 3.5 Let α1 , α2 be two roots in ∆ having the same wall M as their boundary.
Then α1 ∪ α2 is an apartment of ∆ if and only if there exists a panel P ∈ M such that
the chamber C1 ∈ α1 with P ⊆ C1 is different from the chamber C2 ∈ α2 with P ⊆ C2 .
Proof. Obviously, if C1 = C2 , then α1 ∪ α2 cannot be an apartment. So let us assume now
that C1 6= C2 . We first claim that this implies α1 ∩ α2 = M. Indeed, let x be any simplex
in α1 with x ∈
/ M. Then projP x 6= P , because otherwise there would be a minimal gallery
between P and x in some apartment Σ containing α1 , starting with a chamber outside
α1 , which is impossible since α1 is convex and every chamber of Σ containing x has to
be in α1 . Hence P is strictly contained in projP x. But the only simplex in α1 strictly
containing P is C1 , implying projP x = C1 . By assumption, C1 ∈
/ α2 . Hence x cannot
belong to α2 . Similarly, y ∈
/ α1 for any y ∈ α2 \ M. Therefore, α1 ∩ α2 = M.
We now consider apartments Σ1 , Σ2 ∈ A containing α1 , α2 , respectively. Denote by βi the
root opposite αi in Σi , i = 1, 2. By Proposition 3.2, there exists a simplicial isomorphism
ϕ : Σ1 → Σ2 which fixes Σ1 ∩ Σ2 pointwise. So in particular ϕ is the identity on M. This
implies that ϕ(α1 ) has again M as its bounding wall, i.e., ϕ(α1 ) = α2 or ϕ(α1 ) = β2 . We
may assume ϕ(α1 ) = β2 as otherwise we simply compose ϕ with the reflection in Σ2 about
the wall M, and this reflection interchanges α2 with β2 (and note that this composite map
still fixes M pointwise). We now define a simplicial map ρ : α1 ∪ α2 → Σ2 by ρ|α2 = idα2
and ρ|α1 = ϕ|α1 .
Note that ρ is well defined since α1 ∩ α2 = M and ϕ|M = idM . It is also clear that ρ is
a simplicial morphism. Next we define σ : Σ2 → α1 ∪ α2 by σ|α2 = idα2 and σ|β2 = ϕ−1
|β2 .
Again, σ is a well defined simplicial morphism (here we use α2 ∩ β2 = M), and it is
obvious that σ and ρ are inverse to each other. Hence σ : Σ2 → α1 ∪ α2 is a simplical
isomorphism. It follows that α1 ∪ α2 = σ(Σ2 ) is an apartment of ∆, by Proposition 4.59
in [2] (note that the application of the latter does not require σ to be type-preserving,
although it is easy to see that it is here).
8
We mention a consequence of this lemma, thereby slightly improving Lemma 2.2 of [3].
We denote the set of chambers containing a given panel P by CP .
Corollary 3.6 Given a panel P and a wall M in ∆ with P ∈ M. There exists a family
(αC )C∈CP of roots with the following properties.
(1) C ∈ αC , for all C ∈ CP ;
(2) M is the boundary wall of αC ;
(3) αC ∪ αD is an apartment of ∆, for all C, D ∈ CP with C 6= D.
Proof. Let Σ0 be any apartment containing M, and let C0 , D0 ∈ CP be the two chambers
in Σ0 containing P , with C0 6= D0 . Let αC0 , αD0 be the roots in Σ0 which are bounded
by the wall M and contain the chambers C0 , D0 , respectively.
Now, for any C ∈ CP \ {C0 , D0 }, there exists an apartment ΣC containing αC0 ∪ {C}
(direct by Proposition 3.3). Let αC be the root in ΣC with bounding wall M (note that
M ⊆ αC0 ⊆ ΣC ) and containing C. Given two distinct elements C, D ∈ CP , the two roots
αC and αD have the wall M in common, but they do not share the same chambers C and
D, respectively, through P ∈ M. So we can apply Lemma 3.5 and infer that αC ∪ αD is
an apartment of ∆.
The following technical lemma will be needed in the proof of the Main Lemma in Section 4.
Before we state it, we recall the definition of links and stars. If Ω is an arbitrary simplicial
complex and A is a simplex in Ω, we define the link of A in Ω as the subcomplex
LkΩ (A) = {B ∈ Ω | A ∪ B is a simplex in Ω and A ∩ B = ∅},
and the star of A in Ω as
StΩ (A) = {B ∈ Ω | A ∪ B is a simplex in Ω}.
Recall that for A ∈ ∆, Lk∆ (A) is again a building (with apartments LkΣ (A) for all
apartments Σ of ∆ containing A).
Lemma 3.7 Let M be a wall in ∆, let A be a simplex of M and let LA := Lk∆ (A) be
its link in ∆. Then for every apartment ΣA of the building LA with M ∩ LA ⊆ ΣA , there
exists an apartment Σ of ∆ such that ΣA = Σ ∩ LA and M ⊆ Σ.
9
Proof. In this proof, we will have to combine the simplicial view with the W -metric
approach to buildings. This requires some additional notation.
We set CA = {C ∈ C | A ⊆ C}. If J ⊆ S denotes the cotype of A, then CA is a J-residue
in C, and (CA , δ|CA ×CA ) is a W -metric building of type (WJ , J) which corresponds to the
simplicial building LA = Lk∆ (A). To the apartment ΣA of LA corresponds the apartment
(set of chambers) CA′ := {A ∪ B | B is a chamber of ΣA } of CA . Note that, therefore, CA′
satisfies Condition (⋆) of Proposition 3.4.
We now embark on the proof of the lemma. We first choose a (simplicial) root α
b in ∆
which has M as boundary and set α := Ch(b
α). We then choose a panel P ∈ M with
A ⊆ P and P \ A ∈ ΣA ( recall that M ∩ LA ⊆ ΣA ), and denote by C1 , C2 the two
chambers in CA′ which contain P . Set
αi := {C ∈ CA′ | d(C, Ci) < d(C, C3−i )},
for i = 1, 2. These sets α1 and α2 are the sets of chambers corresponding to the two roots
in ΣA with boundary wall M ∩ LA (which is contained in ΣA by assumption).
STEP I. We first prove the assertion in the special case that α1 ⊆ α. In this case we will
show that there exists an apartment Σ of ∆ with α ∪ α2 ⊆ Ch(Σ).
We want to verify Condition (⋆) for α ∪ α2 . To that aim, we choose three chambers
C, D, E ∈ α ∪ α2 and distinguish some (non-disjoint) cases.
(1) C, D, E ∈ α. Condition (⋆) is satisfied since α is part of an apartment.
(2) C, D, E ∈ α1 ∪ α2 . As remarked above, α1 ∪ α2 = CA′ satisfies Condition (⋆).
(3) C ∈ α; D, E ∈ α1 ∪ α2 . First note that the simplicial roots in LA corresponding to
CA ∩ α and α1 have the same wall M ∩ LA . Since α1 ⊆ CA ∩ α, they must be equal.
Now set C ′ := projA C ∈ CA ∩ α = α1 . Then, using the standard property of the
projection mapping that δ(C, C ′)δ(C ′ , X) = δ(C, X), for all chambers X ∈ CA (see
Proposition 5.34(2) in [2]), we obtain
δ(C, D)δ(D, E) = δ(C, C ′)δ(C ′ , D)δ(D, E) = δ(C, C ′ )δ(C ′ , E) = δ(C, E),
where we also used the fact that CA′ satisfies Condition (⋆).
(4) C, D ∈ α; E ∈ α1 ∪ α2 .
10
Set C ′ := projA C and D ′ := projA D. As in (3), we have C ′ , D ′ ∈ α1 . Then, again
using the above mentioned standard property of projections, we obtain
δ(C, D)δ(D, E) =
=
=
=
=
δ(C, C ′)δ(C ′ , D)δ(D, E)
since C, C ′ , D ∈ α,
δ(C, C ′)δ(C ′ , D)δ(D, D ′)δ(D ′ , E)
by (3),
′
′
′
′
′
δ(C, C )δ(C , D )δ(D , E)
since C , D, D ′ ∈ α,
δ(C, C ′)δ(C ′ , E)
since C ′ , D ′, E ∈ α1 ∪ α2 ,
δ(C, E)
by (3).
Now the other cases all follow easily:
(5) C ∈ α1 ∪ α2 ; D, E ∈ α. The claim follows from (4) by taking inverses.
(6) C, E ∈ α; D ∈ α2 . By (4), we have δ(C, D) = δ(C, E)δ(E, D), hence
δ(C, D)δ(D, E) = δ(C, E)δ(E, D)δ(D, E) = δ(C, E).
(7) C, D ∈ α1 ∪ α2 ; E ∈ α. Follows from (3) by taking inverses.
(8) C, E ∈ α1 ∪ α2 ; D ∈ α. Using (3), we have
δ(C, D)δ(D, E) = δ(C, D)δ(D, C)δ(C, E) = δ(C, E).
So, by Proposition 3.4, there is an apartment Σ of ∆ with α ∪ α2 ⊆ Ch(Σ). Hence Σ
contains M (the boundary of α
b) and also ΣA (since CA′ ⊆ Ch(Σ)). Therefore, Σ ∩ LA
contains ΣA . However, since Σ ∩ LA is also an apartment of LA (because A ∈ Σ), we must
have Σ ∩ LA = ΣA , and the assertion follows.
STEP II. We now reduce the general case to the case handled in Step I.
We first observe that α
b ∩ LA is a root in LA with M ∩ LA as bounding wall. Recall that
this is also the common wall of the roots α
b1 , α
b2 in LA corresponding to α1 , α2 , respectively.
Let C be the chamber of α which contains the panel P introduced in the beginning of this
proof. Without loss of generality, we may assume that C 6= C1 (otherwise we interchange
the roles of α1 and α2 ). Then, by Lemma 3.5, the union of the two roots α
b ∩ LA and α
b1
e
is an apartment ΣA of LA .
e A . Thus we obtain an apartment
We can now apply Step I to α and to this apartment Σ
e with α ∪ α1 ⊆ Ch(Σ).
e Let α
e Then M is also the boundary
Σ
e be the root opposite α
b in Σ.
e ∩ LA , and that α
wall of α
e. Note that α
b1 is a root in Σ
b1 shares the boundary M ∩ LA
with the two opposite roots α
e ∩ LA and α
b ∩ LA . Therefore, α
b1 = α
e ∩ LA or α
b1 = α
b ∩ LA .
Since C1 6= C, it follows that α
b1 = α
e ∩ LA , and hence α1 ⊆ Ch(e
α). Now we can apply
Step I to Ch(e
α) and ΣA , and the lemma is proved.
11
4
Complete systems of apartments
In this section, we prove our First Main Result. We denote by ∆ an arbitrary thick
building, and A is the complete apartment system of ∆.
The proof of our First Main Result will be by an induction the first step of which is in
fact Proposition 2.1. Hence we first proof Proposition 2.1, which we restate here. Note
that this proposition is contained in [2] in the form of the exercises 5.83 and 5.84.
Proposition 4.1 If κ is a convex chamber subcomplex of an apartment Σ of ∆, then
there exists an apartment Σ′ of ∆ such that κ = Σ ∩ Σ′ .
Proof. We may assume κ 6= Σ (otherwise set Σ′ = Σ). Let M be the set of walls of
Σ containing some panel P ∈ κ with the property that κ contains exactly one chamber
through P . The set M is not empty since Σ is connected and κ 6= Σ. We choose an
index set J such that M = {Mj | j ∈ J} and, for each j ∈ J, a panel Pj contained in
Mj ∩ κ so that Pj is contained in precisely one chamber of κ. Furthermore, we denote
by Cj , Dj , j ∈ J, the two chambers of Σ containing Pj , with Cj ∈ κ and consequently
Dj ∈
/ κ. Let αj , j ∈ J, be the root of Σ containing Cj but not Dj , which implies that Mj
is the boundary of αj . Since κ is a convex chamber subcomplex of the apartment Σ, we
easily see that κ ⊆ αj , for all j ∈ J. Hence
\
κ⊆
αj .
j∈J
Now suppose, by way of contradiction, that some simplex X is contained in αj , for all
j ∈ J, but not in κ. By considering a minimal gallery joining X to κ, and taking into
account that the intersection of all αj , j ∈ J, is convex itself, we see that we may assume
that X is a chamber adjacent to some chamber X ′ of κ. By construction, there exists
i ∈ J such that X ∩ X ′ ⊆ Mi . We now obtain the contradiction X, X ′ ∈ αi .
Hence we have shown that κ is the intersection of all roots αj , for j ranging over J. Since
∆ is thick, we can choose, for all j ∈ J, a chamber Dj′ ⊇ Pj , with Cj 6= Dj′ 6= Dj , and we
consider the sets
L = κ ∪ {Dj | j ∈ J}, and L′ = κ ∪ {Dj′ | j ∈ J}.
We now claim that the mapping ϕ : C(L) → C(L′ ), which is the identity on C(κ) and
maps Dj onto Dj′ , for all j ∈ J, is a W -isometry. To that aim, we consider for each pair
12
i, j ∈ J, i 6= j, a minimal gallery γij joining Ci with Cj (and entirely contained in κ). We
extend this to a gallery
λij = (Di , Ci , . . . , Cj , Dj ).
| {z }
γij
Since Mi 6= Mj , and since neither Mi nor Mj cross the gallery γij (because κ is contained
in αi and αj ), we see that λij is a gallery in Σ crossing every wall of Σ at most once.
This implies that λij is a minimal gallery. If we put si = δ(Ci, Di ), for all i ∈ J, then
δ(Di , Dj ) = si δ(Ci , Cj )sj , for all pairs i, j ∈ J, i 6= j.
Now the gallery
λ′ij = (Di′ , Ci , . . . , Cj , Dj′ )
| {z }
γij
has the same type as λij and hence is also reduced. Hence δ(Di′ , Dj′ ) = si δ(Ci , Cj )sj =
δ(Di , Dj ). It now follows rather easily that ϕ is a W -isometry (the proof of δ(Di , X) =
δ(Di′ , X), for all i ∈ I and all X ∈ Ch(κ), is similar to that of δ(Di , Dj ) = δ(Di′ , Dj′ )
above). Since L is contained in an apartment, namely in Σ, the extension theorem, or
equivalently, Proposition 3.4, implies that L′ is contained in some apartment Σ′ ∈ A.
Define κ′ := Σ ∩ Σ′ . Then, by the foregoing, κ ⊆ L ∩ L′ ⊆ Σ ∩ Σ′ = κ′ . Hence κ′ is a
convex subcomplex of Σ containing κ, in particular it contains Ci , for all i ∈ J. But it
does not contain Di , because Di ∈
/ Σ′ . Consequently κ′ ⊆ αi , for all i ∈ J. Hence
\
κ′ ⊆
αi = κ
i∈J
and so κ′ = κ.
The proposition is proved.
From now on, for the rest of this section, our standing hypothesis is that each panel of ∆
is contained in at least 4 chambers.
Main Lemma 4.2 For every apartment Σ ∈ A and every wall M in ∆, there exists an
apartment Σ′ ∈ A containing M and satisfying Σ′ ∩ Σ = M ∩ Σ.
Proof. The proof has two main steps: the case M ∩ Σ = ∅ is treated separately, and then
the general case is reduced to the first step using Lemma 3.7.
Case I: M ∩ Σ = ∅.
13
We choose an arbitrary panel P in M and four distinct chambers C1 , C2 , C3 , C4 containing
P . Then, by Corollary 3.6, there exist four roots α1 , α2 , α3 , α4 with boundary wall M
containing C1 , C2 , C3, C4 , respectively, such that Σij := αi ∪ αj is an apartment, for all
i, j ∈ {1, 2, 3, 4}, i 6= j.
The apartment Σ meets every root αi , i ∈ {1, 2, 3, 4}, in a convex subcomplex. If there
are two distinct k, ℓ ∈ {1, 2, 3, 4} such that Σ ∩ αk = Σ ∩ αℓ = ∅, then the assertion follows
by setting Σ′ = Σkℓ . Suppose now that for some j ∈ {1, 2, 3, 4} the intersection Σ ∩ αj
has dimension at least 1, and that for some i ∈ {1, 2, 3, 4} \ {j}, the intersection Σ ∩ αi
is nonempty. Consider the convex subcomplex Θ := Σij ∩ Σ of Σij of dimension at least
1. Then Θ is a chamber complex in its own right (see Proposition 1(ii) in [1]), and, in
particular, Θ is a connected simplicial complex (since dim Θ > 0). By assumption there
exists a vertex x in Σ∩αi , and a vertex y in Σ∩αj . So, we find a path x = x0 , x1 , . . . , xn = y
in Θ connecting x and y (all {xℓ , xℓ+1 } are edges in Θ). Then at least one of the vertices
xk is in M. Indeed, if y ∈ αi , then y = xn ∈ αi ∩ αj = M. If y is not in αi , then there
exists a k with xk ∈ αi and xk+1 ∈
/ αi . In particular, xk+1 is not in M, and hence it is
in the interior of αj , implying {xk , xk+1 } ∈ αj . Hence xk ∈ αi ∩ αj = M. However, we
assumed M ∩ Σ = ∅. So M ∩ Θ 6= ∅ is not possible, and we obtain a contradiction.
So we may assume that for every i ∈ {1, 2, 3, 4}, Σ ∩ αi is either 0-dimensional or empty.
We may also assume that Σ ∩ α1 is 0-dimensional. Let x be a vertex in Σ ∩ α1 . Then, for
all i ∈ {2, 3, 4}, Σ ∩ Σ1i , being a 0-dimensional convex subcomplex of Σ, is contained in
the support of x in Σ by Proposition 3.1. Now, by Proposition 1(iii) of [1], this support,
which is also a 0-dimensional convex subcomplex of Σ, can have at most two vertices.
Hence there is at most one i ∈ {2, 3, 4} with Σ ∩ αi 6= ∅ since Σ ∩ αi is contained in the
support of x in Σ and the intersections Σ ∩ αj , for j ∈ {1, 2, 3, 4}, are pairwise disjoint
(because M ∩ Σ = ∅). Hence we can put Σ′ = αk ∪ αℓ , with k and ℓ distinct in {2, 3, 4}
such that Σ ∩ αk = Σ ∩ αℓ = ∅.
Case II: M ∩ Σ 6= ∅.
Choose a maximal simplex A in M ∩ Σ and set LA := Lk∆ (A), MA := M ∩ LA and
ΣA := LkΣ (A) = Σ ∩ LA . Then MA is a wall in LA , ΣA is an apartment of LA and
MA ∩ ΣA = ∅ since A is maximal in M ∩ Σ. Applying Case I to MA and ΣA , we find an
apartment Σ′A of LA containing MA and satisfying Σ′A ∩ ΣA = ∅. In view of Lemma 3.7
we can find Σ′ ∈ A with Σ′A = Σ′ ∩ LA and M ⊆ Σ′ . This implies that A is maximal
in Σ′ ∩ Σ (noting A ⊆ B ∈ Σ′ ∩ Σ implies B \ A ∈ Σ′A ∩ ΣA = ∅). And Σ′ ∩ Σ is a
convex subcomplex of Σ′ . Then Σ′ ∩ Σ ⊆ M by Proposition 3.1, because A ∈ M. Hence
Σ′ ∩ Σ = Σ′ ∩ Σ ∩ M = (Σ′ ∩ M) ∩ Σ = M ∩ Σ.
14
Theorem 4.3 Let ∆ be a building with the property that each of its panels is contained
in at least four chambers, and let κ be a convex subcomplex of an apartment Σ of ∆. Then
there exists an apartment Σ′ of ∆ such that Σ′ ∩ Σ = κ.
Proof. The proof goes by induction on the codimension codim(κ). The case codim(κ) = 0
is settled by Proposition 4.1. So let us assume codim(κ) > 0. Choose a maximal simplex
A of κ. Recall that κ is a chamber complex (see [1], Proposition 1(ii)). This implies in
particular dim A = dim κ < dim Σ. So there exists a panel P in Σ with A ⊆ P . Denote
by M the wall of Σ containing P . Then κ ⊆ M by Proposition 3.1.
Let C1 , C2 be the two chambers of Σ which contain P . Let x1 be the vertex in C1 \ P ,
i.e. C1 = P ∪ {x1 }, and set A1 := A ∪ {x1 }. Note that x1 ∈
/ M and hence A1 ∈
/ M. Now
let κ1 be the convex hull of κ ∪ {A1 } in Σ. Then dim κ1 = dim A1 . Indeed, let M ′ be any
wall of Σ containing A1 . Then M ′ contains κ by Proposition 3.1 and hence also κ1 since
M ′ is convex and κ ∪ {A1 } ⊆ M ′ . Since this is true for any wall M ′ of Σ containing A1 ,
we see that κ1 is contained in the intersection suppA1 of all these walls (and which we
have called the support of A1 in Σ above). We now claim that A1 is maximal in suppA1 .
Indeed, if A′1 is any element of Σ properly containing A1 , we choose a chamber C ′ of Σ
containing A′1 and a panel P ′ of C ′ with A1 ⊆ P ′ and A′1 6⊆ P ′ . Then the wall through
P ′ contains A1 but not A′1 , since it does not contain C ′ = P ′ ∪ {A′1 }. Hence the claim.
Therefore dim κ1 = dim(suppA1 ) = dim A1 = 1 + dim A.
In particular, we can apply the induction hypothesis to κ1 , which gives us an apartment
Σ1 of ∆ satisfying Σ1 ∩ Σ = κ1 .
Now let D1 be a chamber of Σ1 containing A1 , and let P1 be the panel P1 = D1 \ {x1 }. So
P1 contains A but not A1 . Denote by M1 the wall of Σ1 containing P1 . We see that M1
also contains A but not A1 . By Proposition 3.1, this implies first of all κ ⊆ M1 (note that
κ is also a convex subcomplex of Σ1 since κ is convex in ∆). Secondly, A is maximal in
M1 ∩ κ1 . Indeed, if not, then M1 would contain some simplex strictly bigger than A and
hence of dimension dim A + 1 = dim κ1 . But then Proposition 3.1 would imply κ1 ⊆ M1 ,
contradicting A1 ∈
/ M1 . Hence dim(M1 ∩ κ1 ) = dim A = dim κ.
We now claim that M1 ∩ κ1 = κ. The inclusion κ ⊆ M1 ∩ κ1 is clear (we verified κ ⊆ M1
above). Now let β be any root of Σ1 containing κ. If β contains x1 , it also contains
A1 = A ∪ {x1 } and hence κ1 . If β does not contain x1 , then A, which is in β and which
is joinable to x1 , must be contained in the wall N which bounds β. However, we showed
above that A is maximal in M1 ∩κ1 . Hence A ∈ N implies M1 ∩κ1 ⊆ N by Proposition 3.1.
So for any root β of Σ1 which contains κ we have M1 ∩κ1 ⊆ β. Hence M1 ∩κ1 is contained
in the intersection of all these roots β, and this intersection is equal to κ because κ is a
convex subcomplex of Σ1 . So we have also proved M1 ∩ κ1 ⊆ κ, and the claim follows.
15
Recall that κ1 = Σ1 ∩ Σ. Hence the previous claim immediately implies M1 ∩ Σ =
M1 ∩ Σ1 ∩ Σ = M1 ∩ κ1 = κ. Applying Lemma 4.2, we find an apartment Σ′ of ∆ which
contains M1 and satisfies Σ′ ∩ Σ = M1 ∩ Σ = κ.
Corollary 4.4 If κ is a convex subcomplex of Σ with dim κ < dim Σ, then there exists a
wall M in Σ containing κ, and for each such wall M there exists some wall M ′ in ∆ such
that κ = M ∩ M ′ .
Proof. Choose the apartment Σ′ as in Theorem 4.3 such that Σ′ ∩ Σ = κ. Let A be
a maximal simplex of κ and choose walls M, M ′ in Σ, Σ′ , respectively, with A ∈ M and
A ∈ M ′ (this is possible since dim A = dim κ < dim Σ = dim Σ′ ). Then by Proposition 3.1,
κ ⊆ M and κ ⊆ M ′ . So we have
κ ⊆ M ∩ M ′ ⊆ Σ ∩ Σ′ = κ,
and the assertion follows.
5
Incomplete systems of apartments
In this section we show our Second Main Result.
We start with a proposition that motivates our restriction to consider solely finite convex
subcomplexes in the sequel.
Proposition 5.1 Let ∆ be a thick building and let Σ be an apartment (in the complete
apartment system A of ∆). Let κ be an infinite subset of Σ. Then the family A∗ = {Σ∗ ∈
A | κ 6⊆ Σ∗ } is a system of apartments for ∆. In particular, A′ = A∗ ∪ {Σ} is also a
system of apartments for ∆, and κ is contained in a unique member of A′ . Hence if κ is
any infinite proper convex subcomplex of Σ, it cannot be the intersection of all apartments
of A′ in which it is contained.
Proof. Let C, D be two chambers of ∆. Then the convex hull H of C, D is contained in
some apartment ΣH ∈ A. Since H is convex, Proposition 4.1 implies the existence of an
apartment Σ′H ∈ A such that ΣH ∩ Σ′H = H. Since H is finite, we have κ 6⊆ H and so κ
cannot be contained in both of ΣH and Σ′H . Hence at least one of these is a member of
A∗ .
The assertion now follows easily.
16
Theorem 5.2 Let ∆ be a thick building of type (W, S). Then the following are equivalent.
(I) For any apartment system A of ∆, the convex closure of two given chambers C and
D is precisely the intersection of two apartments in A containing C and D.
(II) For any apartment system A of ∆, every finite convex chamber subcomplex κ contained in some member of A is precisely the intersection of two apartments in A
containing κ.
(III) For every finite subset F of chambers of the standard Coxeter complex Σ(W, S),
there exist two chambers C, D ∈ Σ(W, S) such that F is contained in the convex
closure of C and D.
(IV) For every triplet {X, Y, Z} of chambers of the standard Coxeter complex Σ(W, S),
there exist two chambers C, D ∈ Σ(W, S) such that {X, Y, Z} is contained in the
convex closure of C and D.
Proof. We show (IV)⇒(III)⇒(II)⇒(I)⇒(IV), where the last implication requires most of
the work.
(1) (IV)⇒(III). We use induction on |F | ≥ 3. For |F | = 3, this is precisely (IV). Now let
|F | > 3 and choose Z ∈ F arbitrary. Then, by the induction hypothesis, there exist two
chambers X, Y in Σ(W, S) such that F \ {Z} is contained in the convex closure of X and
Y . Applying (IV) to X, Y, Z gives us the desired pair C, D of chambers.
(2) (III)⇒(II). Denote by Ae the complete apartment system of ∆. Suppose κ ⊆ Σ ∈ A.
e of Ae such that κ = Σ ∩ Σ.
e We may assume
By Proposition 4.1, there exists a member Σ
e
Σ∈
/ A. Define
e | E has a panel in κ}.
κ := {E ∈ Ch(Σ)
e
Since e
κ is clearly a finite set, (III) implies that e
κ is contained in the convex hull H of
′
e
two chambers X, Y of Σ. Let now Σ be a member of A containing X, Y . We claim that
κ = Σ ∩ Σ′ . Indeed, we clearly have κ ⊆ Σ ∩ Σ′ , so assume by way of contradiction that
Σ∩Σ′ 6⊆ κ. Then there are adjacent chambers C, D with C ∈ κ, D ∈
/ κ and C, D ∈ Σ∩Σ′ .
By definition of e
κ, each panel P contained in κ is contained in precisely two chambers
of e
κ. Since κ
e ⊆ H ⊆ Σ′ , these are the two chambers in Σ′ which contain P . So the two
chambers of Σ′ containing P are in fact contained in e
κ. Applied to P = C ∩ D, we obtain
e = κ, a contradiction. The claim is proved, and so is Assertion
C, D ∈ κ
e. Hence D ∈ Σ∩ Σ
(II).
17
(3) (II)⇒(I). This is obvious since the convex closure of two chambers always contains a
finite number of chambers.
(4) (I)⇒(IV). Given three chambers X, Y, Z in some apartment Σ of ∆, we show that
there exist two chambers C, D in Σ such that X, Y, Z are contained in the convex hull of
C and D. This is trivial if Z is contained in the convex closure of X and Y . So we may
assume that Z is not contained in that convex closure. We first prove (IV) in the special
case that Z is adjacent to some chamber E of the convex closure of X and Y . So assume,
by way of contradiction, that there are three chambers C1 , C2 , C3 in some apartment Σ,
with C3 adjacent to some chamber E of the convex closure θ of C1 and C2 , but C3 does
not belong to θ, such that the convex closure of any two chambers C, D of Σ does not
contain all of them.
Let Ae be the complete system of apartments for ∆, and let A be the subset of Ae consisting
of those apartments that either do not contain {C1 , C2 } or contain {C1 , C2 , C3 }. We show
that A is a system of apartments for ∆. It suffices to show that any two chambers U, V
are contained in a member of A. Let κ be the convex closure of U and V . Choose an
apartment Σ′ ∈ Ae with U, V ∈ Σ′ and hence κ ⊆ Σ′ . If {C1 , C2 } 6⊆ κ, then we choose,
using Proposition 4.1, another apartment Σ′′ ∈ Ae such that κ = Σ′ ∩ Σ′′ . Then not both
of Σ′ and Σ′′ contain {C1 , C2 }, and hence at least one of Σ′ and Σ′′ is in A.
Suppose now that {C1 , C2 } ⊆ κ. Let E ′ be the chamber of Σ′ which contains the panel
P = E ∩ C3 and is distinct from E. We first show that E ′ ∈
/ κ. For this, let ϕ : Σ′ → Σ
be the isomorphism fixing Σ′ ∩ Σ (and hence θ) pointwise (see Proposition 3.2). Then
the convex hull ϕ(κ) of ϕ(U) and ϕ(V ) contains ϕ(θ) = θ. If E ′ ∈ κ, then ϕ(κ) also
contains ϕ(E ′ ). Since ϕ(E ′ ) is a chamber of Σ with ϕ(E ′ ) 6= ϕ(E) = E and P = ϕ(P ) ⊆
ϕ(E ′ ), we must have ϕ(E ′ ) = C3 . So the convex closure of ϕ(U) and ϕ(V ) contains
ϕ({C1, C2 , E ′ }) = {C1 , C2 , C3 }, contradicting our assumption. Consequently we must
have E ′ ∈
/ κ.
Now let α be the root in Σ′ containing E but not E ′ . Since κ is convex, E ∈ κ and E ′ ∈
/ κ,
it follows that κ ⊆ α. Since we assume {C1 , C2 } ⊆ κ, also θ ⊆ α. By Proposition 3.3,
there exists an apartment Σ′′ ∈ Ae with α ∪ {C3 } ⊆ Σ′′ . Since {C1 , C2 , C3 } ⊆ Σ′′ , we have
Σ′′ ∈ A. This completes the proof that A is a system of apartments for ∆.
However, the convex closure of C1 and C2 can not be equal to the intersection of two
apartments of A containing both of C1 and C2 since the former does not contain C3 and
the latter always does. This contradicts Assumption (I). So C1 , C2 , C3 as described cannot
exist. Consequently, if Z is adjacent to a chamber of the convex closure of X and Y , then
{X, Y, Z} is contained in the convex closure of two chambers of Σ.
18
We now prove the general case by induction on the gallery distance n from Z to the
convex closure of X, Y . If n = 1, then this is the foregoing. If n > 1, then there is a
chamber Z ′ adjacent to Z and at distance n − 1 from the convex closure of X, Y . The
induction hypothesis implies the existence of two chambers C ′ , D ′ in Σ such that X, Y, Z ′
are contained in the convex closure of C ′ , D ′. Applying the above to {C ′ , D ′ , Z}, the
assertion is now clear.
Since every apartment of ∆ is isomorphic to the standard Coxeter complex Σ(W, S), the
equivalence of (I) up to (IV) is proved completely.
For the classification of Coxeter complexes satisfying Condition (III) of the above theorem,
we refer to [4], Theorem 7.2. Necessary and sufficient is that each irreducible component is
affine or spherical. Since spherical buildings are automatically endowed with the complete
system of apartments, we may restrict to the irreducible affine case to state the following
proposition.
Proposition 5.3 Let ∆ be an irreducible building of affine type with given apartment
system A, and suppose each panel is contained in at least four chambers. Then every
finite convex subcomplex κ contained in some apartment Σ ∈ A is the intersection of Σ
with some other member Σ′ ∈ A.
e ∈ Ae
Proof. Let Ae be the complete system of apartments. By Theorem 4.3, there exists Σ
e
such that κ = Σ ∩ Σ. Now denote by Vert(κ) the set of vertices of κ and define
[
κ
e :=
StΣe (x).
x∈Vert(κ)
e Hence e
Then κ
e is the union of a finite set of chambers of Σ.
κ is contained in the convex
′
hull of two chambers, and there exists Σ ∈ A with e
κ ⊆ Σ′ . For every x ∈ Vert(κ), the
links LkΣe (x) and LkΣ′ (x) are two apartments in Lk∆ (x) with LkΣe (x) ⊆ LkΣ′ (x), since
StΣe (x) ⊆ Σ′ . Hence LkΣe (x) = LkΣ′ (x), and consequently also StΣe (x) = StΣ′ (x), implying
[
κ=
e
StΣ′ (x).
x∈Vert(κ)
We claim that Σ ∩ Σ′ = κ. Indeed, since κ is certainly contained in both of Σ and Σ′ , we
may assume by way of contradiction that some vertex y is contained in Σ ∩ Σ′ but not in
κ. By connectivity of Σ ∩ Σ′ (recall that apartments in affine buildings are geodesically
convex), this implies that there is some edge {x, x′ }, with x ∈ κ, and with x′ ∈ Σ ∩ Σ′
19
e Since x′ also belongs to Σ, we obtain
κ ⊆ Σ.
and not in κ. Hence x′ ∈ StΣ′ (x) and so x′ ∈ e
e = κ.
the contradiction x′ ∈ Σ ∩ Σ
The proposition is proved.
Remark 5.4 If κ contains a chamber, the above proof yields (referring to Proposition 4.1
instead of Theorem 4.3) the same result without the assumption that each chamber of
the thick building ∆ is contained in at least four chambers.
We now prove Proposition 2.5.
Proposition 5.5 For every thick building ∆ and every apartment system A of ∆, the
subcomplex formed by two adjacent chambers is always the intersection of all members of
A containing both of those chambers.
Proof. Let C and D be two adjacent chambers of ∆. Let E be a chamber in the intersection
of all apartments containing both of C and D, and assume, by way of contradiction that
E∈
/ {C, D}. By convexity, we may assume that E is adjacent to one of C, D, and without
loss of generality, we may assume E is adjacent to D, and hence not to C. Let E ′ be a
third chamber containing the panel D ∩ E, E ′ ∈
/ {D, E}. Then any apartment containing
C and E ′ contains D (since (C, D, E ′) is a minimal gallery) and does not contain E, a
contradiction.
The proposition is proved completely.
We end this paper with an application of the last result.
Proposition 5.6 Let ∆ be a thick building, and let ∆′ be an arbitrary building. Let ∆
and ∆′ be endowed with arbitrary systems of apartments A and A′ , respectively. Let ϕ
be a map from Ch(∆) to Ch(∆′ ). Suppose that ϕ bijectively maps the set of chambers
of any apartment Σ ∈ A to the set of chambers of some apartment Σ′ ∈ A′ . Then ϕ is
injective and preserves adjacency of chambers (i.e., any two chambers of ∆ are adjacent
if and only if their images under ϕ are). Furthermore, ϕ(Ch(∆)) is the set of chambers
of a thick subbuilding of ∆′ . Hence ϕ induces a simplicial isomorphism of ∆ onto a thick
subbuilding of ∆′ in case ∆ is 2-spherical.
Proof. First note that ϕ is injective. Indeed, this follows from the fact that ϕ is injective
when restricted to the set of chambers of any apartment, and the fact that every pair of
20
chambers is contained in at least one apartment. Secondly, note that the image ϕ(Ch(∆))
is the chamber set of a subbuilding of ∆′ with ϕ(A) (obvious notation) as apartment system. Indeed, we only need to check that every pair ϕ(C), ϕ(D) of chambers of ϕ(Ch(∆))
is contained in an element of ϕ(A) (with C, D chambers of ∆). But that follows immediately from our assumptions. Hence, form now on, we may assume that ϕ(Ch(∆))
coincides with Ch(∆′ ), and that A′ is the set of all images under ϕ of the members of A.
We now show that ∆′ is thick. Let P be a panel of ∆′ contained in the two chambers
ϕ(C) and ϕ(D). Then, considering any chamber of ∆ adjacent to C and different from D,
we can use Proposition 5.5 to see that there exists some apartment Σ ∈ A containing C
but not D. Let E ′ be the unique chamber of ϕ(Ch(Σ)) adjacent to ϕ(C) and containing
P (recall that ϕ(Ch(Σ)) = Ch(Σ′ ), for some Σ′ ∈ A′ ). Since D ∈
/ Σ, it follows from global
injectivity that E ′ 6= ϕ(D). This shows thickness of ∆′ .
Now we show that ϕ preserves adjacency. Let C, D be adjacent in ∆. Then the intersection
of all apartments in A′ containing ϕ(C) and ϕ(D) contains every chamber of the convex
hull H of ϕ(C) and ϕ(D). Let ϕ(E) be a chamber in H. Then E is contained in
every apartment in A containing C, D. By Proposition 5.5, E ∈ {C, D}, and hence
ϕ(E) ∈ {ϕ(C), ϕ(D)}. So we have proved that ϕ(C) and ϕ(D) are the only chambers in
H, showing that ϕ(C) and ϕ(D) are adjacent. Interchanging the roles of ∆ and ∆′ , we
also see that ϕ−1 maps adjacent chambers to adjacent chambers.
In view of Proposition 3.21 of [6], the proposition is completely proved.
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21
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[9] J. Tits, Twin buildings and groups of Kac-Moody type, in “Groups, Combinatorics
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Addresses of the authors:
Peter Abramenko
Department of Mathematics
University of Virginia
P.O.Box 400137
Charlottesville, VA 22904
USA
[email protected]
Hendrik Van Maldeghem
Department of Pure Mathematics and Computer Algebra
Ghent University
Krijgslaan 281, S22
9000 Gent
Belgium
[email protected]
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